Advertisements
Advertisements
प्रश्न
From the following data, N = 11, ∑X = 117, ∑Y = 260, ∑X2 = 1313, ∑Y2 = 6580, ∑XY = 2827 the correlation coefficient is
विकल्प
0.3566
– 0.3566
0
0.4566
Advertisements
उत्तर
0.3566
Explanation:
r = `("N"sum"XY" - sum"X"sum"Y")/(sqrt("N"sum"X"^2 - (sum"X")^2) sqrt("N"sum"Y"^2 - (sum"Y")^2))`
= `(11 xx 2827 - 117 xx 260)/(sqrt (11 xx 1313 - (117)^2) sqrt (11 xx 6580 - (260)^2))`
= `(31097 xx 30420)/(sqrt(14443 - 13689) sqrt (72380 - 67600))`
= `677/(sqrt 754 sqrt 4780)`
= `677/sqrt3604120`
= `677/1898.45`
= 0.3566
APPEARS IN
संबंधित प्रश्न
Find the coefficient of correlation for the following:
| Cost (₹) | 14 | 19 | 24 | 21 | 26 | 22 | 15 | 20 | 19 |
| Sales (₹) | 31 | 36 | 48 | 37 | 50 | 45 | 33 | 41 | 39 |
Calculate the coefficient of correlation between X and Y series from the following data.
| Description | X | Y |
| Number of pairs of observation | 15 | 15 |
| Arithmetic mean | 25 | 18 |
| Standard deviation | 3.01 | 3.03 |
| Sum of squares of deviation from the arithmetic mean | 136 | 138 |
Summation of product deviations of X and Y series from their respective arithmetic means is 122.
If the values of two variables move in the opposite direction then the correlation is said to be
Correlation co-efficient lies between
If r(X,Y) = 0 the variables X and Y are said to be
The correlation coefficient
The person suggested a mathematical method for measuring the magnitude of linear relationship between two variables say X and Y is
If r = – 1, then correlation between the variables
Calculate the correlation coefficient from the following data:
∑X = 125, ∑Y = 100, ∑X2 = 650, ∑Y2 = 436, ∑XY = 520, N = 25
If both variables X and Y increase or decrease simultaneously, then the coefficient of correlation will be:
