Question

From the equation:

\[\ce{C + 2H2SO4 -> CO2 + 2H2O + 2SO2}\]

Calculate the volume of sulphur dioxide measured at STP,  liberated at the same time.

Answer 1

\[\ce{\underset{12 g}{C2} + \underset{2(98)}{2H2SO4} -> CO2 + 2H2O + 2SO2}\]

12 g of carbon will liberate (22.4 × 2) litres of SO₂

1 g of carbon will liberate `(22.4 xx 2)/12` litres of SO₂

3 g of carbon will liberate `(22.4 xx 2)/12 xx 3` litres of SO₂ = 11.2 litres of SO₂