Question

From \[\begin{bmatrix}2a+b&a-2b\\5c-d&4c+3d\end{bmatrix}=\begin{bmatrix}4&-3\\11&24\end{bmatrix},\] which equation is obtained by equating the corresponding elements in position \[(1,2)\]?

विकल्प

• \[2a+b=4\]

• \[4c+3d=24\]

• \[5c-d=11\]

• \[a-2b=-3\]

Answer 1

The element in position \[(1,2)\] of the first matrix is \[a-2b\]. The corresponding element in the second matrix is \[-3\].