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प्रश्न
For what value of a the point (a, 1), (1, –1) and (11, 4) are collinear?
योग
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उत्तर
Let A(a, 1), B(1, –1) and (11, 4) be the given point
Area of ΔABC
`=1/2{a(-1-4)+1(4-1)+11(1+1)} `
`=1/2 {-5+3+22}`
`=1/2{-5a+25}`
For the point to be collinear
Area of ΔABC = 20
`1/2{-5a+25}=0`
`=>-5a+25=0`
`=>-5a=-25`
`=>a=5`
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