Advertisements
Advertisements
प्रश्न
For the set of numbers given below, find mean: 3, 0, 5, 2, 6, 2
Advertisements
उत्तर
Mean = `(sumx)/"N"`
Mean
= `(3 + 0 + 5 + 2 + 6 + 2)/(6)`
= (18)/(6)`
= 3..
APPEARS IN
संबंधित प्रश्न
The mean of 15 observations is 32. Find the resulting mean, if the observation is: Decreased by 20%
Find the mean of 8, 12, 16, 22, 10 and 4. Find the resulting mean, if the observations, given above, be: multiplied by 3 and then divided by 2.
The mean of 18, 24, 15, 2x + 1 and 12 is 21. Find the value of x.
The heights (in cm) of the volleyball players from team A and team B were recorded as:
Team A: 180, 178, 176, 181, 190, 175, 187
Team B: 174, 175, 190, 179, 178, 185, 177
Which team had a greater average height?
Find the median of team A and team B.
The average of n numbers x1, x2, x3 ….. xn is A. If x1 is replaced by ( x+ α )x1, x2, is replaced by ( x+ α )x2 and so on.
Find the new average.
Find the mean of the following data: 30, 32, 24, 34, 26, 28, 30, 35, 33, 25
(i) Show that the sum of the deviations of all the given observations from the mean is zero.
(ii) Find the median of the given data.
For the set of numbers given below, find mean: 5, 7, 8, 4, 6
A test out of 25 marks was given to 16 students and marks scored are recorded below: 25, 8, 14, 20, 16, 22, 10, 15, 8, 7, 24, 18, 19, 6, 11, 14
In the report, marks were entered out of 50. What is the mean of the recorded marks in the report?
In History project, marks out of 20 were awarded to 8 students. The marks were as shown below:
14, 16, 18, 14, 16, 14, 12, 16
Find the mean marks.
In History project, marks out of 20 were awarded to 8 students. The marks were as shown below: 14, 16, 18, 14, 16, 14, 12, 16
Each of the above students was 2 extra marks for submitting the project a week before the due date. What is the revised mean of this group?
