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प्रश्न
For the following bond cleavages, use curved-arrows to show the electron flow and classify as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
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उत्तर
The bond cleavage using curved-arrows to show the electron flow of the given reaction can be represented as
It is an example of heterolytic cleavage as the bond breaks in such a manner that the shared pair of electrons remains with the carbon of propanone. The reaction intermediate formed is carbanion.
संबंधित प्रश्न
For the following bond cleavages, use curved arrows to show the electron flow and classify homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
\[\ce{CH3O - OCH3 -> CH3\overset\bullet{\text{O}} + \overset\bullet{\text{O}}CH3}\]
For the following bond cleavages, use curved-arrows to show the electron flow and classify as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
For the following bond cleavages, use curved-arrows to show the electron flow and classify as homolysis or heterolysis. Identify reactive intermediate produced as free radical, carbocation and carbanion.
Which of the following carbocation is most stable?
What is the correct order of decreasing stability of the following cations.
| I. | \[\ce{CH3 - \overset{⊕}{C}H - CH3}\] |
| II. | \[\ce{CH3 - \overset{⊕}{C}H - OCH3}\] |
| III. | \[\ce{CH3 - \overset{⊕}{C}H - CH2 - OCH3}\] |
Match the intermediates given in Column I with their probable structure in Column II.
| Column I | Column II |
| (i) Free radical | (a) Trigonal planar |
| (ii) Carbocation | (b) Pyramidal |
| (iii) Carbanion | (c) Linear |
Which of the following carbocation's is most stable?
 |
 |
 |
 |
| (I) | (II) | (III) | (IV) |
Among the given species the resonance stabilised carbocations are:
Which of the following is the most stable carbocation?
 |
\[\ce{CH2 = \overset{⊕}{C}H}\] | \[\ce{CH3 - \overset{⊕}{C}H2}\] | \[\ce{HC ≡ \overset{⊕}{C}}\] |
| A | B | C | D |
The correct order of stability of given carbocation is:
A solution of (–) – 1 – chloro–1–phenylethane in toluene racemises slowly in the presence of a small amount of SbCl5, due to the formation of ______.
The increasing order of stability of the following free radicals is ______.
