Advertisements
Advertisements
प्रश्न
For the ellipse \[\frac{x^2}{a^2}+\frac{y^2}{b^2}=1\], which expression for \[y\] is obtained before selecting the first-quadrant branch?
विकल्प
\[y=\pm\frac{a}{b}\sqrt{b^2-x^2}\]
\[y=\pm\frac{b}{a}\sqrt{a^2-x^2}\]
\[y=\frac{b}{a}(a^2-x^2)\]
\[y=\pm\frac{b}{a}\sqrt{x^2-a^2}\]
MCQ
Advertisements
उत्तर
Rearranging the ellipse equation gives \[y^2=\frac{b^2}{a^2}(a^2-x^2)\]. Taking square roots gives the two branches \[y=\pm\frac{b}{a}\sqrt{a^2-x^2}\].
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
