Question

For the decomposition of azomethane

\[\ce{CH3N2CH3_{(g)} -> CH3CH3_{(g)} + N2_{(g)}}\] is a first order reaction, the variation in partial pressure with time at 600 K is given by 

The half-life of the reaction is ______ × 10⁻⁵ s (Nearest integer).

Answer 1

The half-life of the reaction is 2 × 10⁻⁵ s.

Explanation:

For a first-order reaction, the rate law is given by:

`ln(P/P^circ) = -kt`

So the slope of the straight line = −k.

Thus,

k = 3.465 × 10⁴ s⁻¹    ...[Given]

The half-life t_1/2​ for a first-order reaction is given by:

`t_(1//2) = (ln 2)/k`

= `0.693/(3.465 xx 10^4)`

= `0.693/34650`

= 2 × 10⁻⁵ s

∴ The half-life of the reaction is 2 × 10⁻⁵ s.