Question

For \[n\] cells connected in series in the same sense, the correct relations are:

विकल्प

• \[\frac{1}{r_{eq}} = \frac{1}{r_1} + \frac{1}{r_2} + \cdots + \frac{1}{r_n}\] and \[\varepsilon_{eq} = \varepsilon_1 - \varepsilon_2\]

• \[\varepsilon_{eq} = \frac{\varepsilon_1 + \varepsilon_2 + \cdots + \varepsilon_n}{n}\] and \[r_{eq} = \frac{r_1 + r_2 + \cdots + r_n}{n}\]

• \[\varepsilon_{eq} = \varepsilon_1 + \varepsilon_2 + \cdots + \varepsilon_n\] and \[r_{eq} = r_1 + r_2 + \cdots + r_n\]

• \[\varepsilon_{eq} = \frac{\varepsilon_1 r_2 + \varepsilon_2 r_1}{r_1 + r_2}\] and \[r_{eq} = \frac{r_1 r_2}{r_1 + r_2}\]

Answer 1

For n cells in series in the same sense, both emfs and internal resistances simply add: \[\varepsilon_{eq} = \varepsilon_1 + \varepsilon_2 + \cdots + \varepsilon_n\] and \[r_{eq} = r_1 + r_2 + \cdots + r_n\].