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प्रश्न
For \[f(x)=\begin{cases}1,&x\leq0\\2,&x>0\end{cases}\], why is \[f\] discontinuous at \[x=0\]?
विकल्प
\[\lim_{x\to0^-}f(x)=\lim_{x\to0^+}f(x)=2\].
\[\lim_{x\to0^-}f(x)=\lim_{x\to0^+}f(x)=1\].
\[\lim_{x\to0^-}f(x)=1\] and \[\lim_{x\to0^+}f(x)=2\].
\[f(0)\] is not defined.
MCQ
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उत्तर
The left-hand limit is \[1\], whereas the right-hand limit is \[2\]. Since LHL is not equal to RHL, the limit does not exist.
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