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प्रश्न
For the equation given below, find the slope and the y-intercept:
x + 3y + 5 = 0
योग
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उत्तर
Equation of any straight line in the form y = mx + c, where slope = m(co-efficient of x) and y-intercept = c(constant term)
x + 3y + 5 = 0
x + 3y + 5 = 0
3y = - x - 5
y = `(- x - 5)/(3)`
y = `(-1)/(3) x + (-5/3)`
Therefore,
slope = co-efficient of x = `-(1)/(3)`
y-intercept = constant term = `-(5)/(3)`.
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