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प्रश्न
For the equation given below, find the slope and the y-intercept:
4y + 9 = 0
योग
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उत्तर
Equation of any straight line in the form y = mx + c, where slope = m(co-efficient of x) and y-intercept = c(constant term)
4y + 9 = 0
4y + 9 = 0
4y = 0 · x - 9
y = `(0)/(4) x -(9)/(4)`
y = 0 · x + `(-9/4)`
Therefore,
slope = co-efficient of x = 0
y-intercept = constant term = `-(9)/(4)`
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