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For Any Two Non-zero Vectors, Write the Value of ∣ ∣ → a + → B ∣ ∣ 2 + ∣ ∣ → a − → B ∣ ∣ 2 | → a | 2 + ∣ ∣ → B ∣ ∣ 2 . - Mathematics

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प्रश्न

For any two non-zero vectors, write the value of \[\frac{\left| \vec{a} + \vec{b} \right|^2 + \left| \vec{a} - \vec{b} \right|^2}{\left| \vec{a} \right|^2 + \left| \vec{b} \right|^2} .\] 

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उत्तर

\[\text{ We have }\]
\[\frac{\left| \vec{a} + \vec{b} \right|^2 + \left| \vec{a} - \vec{b} \right|^2}{\left| \vec{a} \right|^2 + \left| \vec{b} \right|^2}\]
\[ = \frac{\left| \vec{a} \right|^2 + \left| \vec{b} \right|^2 + 2 \vec{a} . \vec{b} + \left| \vec{a} \right|^2 + \left| \vec{b} \right|^2 - 2 \vec{a} . \vec{b}}{\left| \vec{a} \right|^2 + \left| \vec{b} \right|^2}\]
\[ = \frac{2\left( \left| \vec{a} \right|^2 + \left| \vec{b} \right|^2 \right)}{\left| \vec{a} \right|^2 + \left| \vec{b} \right|^2}\]
\[ = 2\] 

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अध्याय 24: Scalar Or Dot Product - very short answer [पृष्ठ ४७]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 24 Scalar Or Dot Product
very short answer | Q 16 | पृष्ठ ४७

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