Question

For a rectangular loop whose plane is parallel to \[\vec{B}\] (θ = 90°), the torque is computed as force × perpendicular distance between the two forces, which gives:

विकल्प

• \[\tau = 0\]

• \[\tau = BIb \times b = BIb^2\]

• \[\tau = BIb \times l = BIA\]

• \[\tau = BIl \times l = BIl^2\]

Answer 1

The two forces of magnitude \[F_1 = BIb\] on sides BC and AD are separated by the length l of the loop. Hence \[\tau = F_1 \times l = BIb \times l = BIA\], since \[A = l \times b\]. For N turns, this becomes \[\tau_{max} = NIAB\].