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प्रश्न
Following is the distribution of the long jump competition in which 250 students participated. Find the median distance jumped by the students. Interpret the median
| Distance (in m) |
0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
| Number of Students |
40 | 80 | 62 | 38 | 30 |
योग
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उत्तर
| Distance (in m) |
0 – 1 | 1 – 2 | 2 – 3 | 3 – 4 | 4 – 5 |
| Number of Students |
40 | 80 | 62 | 38 | 30 |
| `cf` | 40 | 120 | 182 | 220 | 250 |
`n/2 = 250/2` = 125 ⇒ median class is 2 – 3, `l` = 2, `h` = 1, `cf` = 120, `f` = 62
Median = `l + (n/2 - cf)/f xx i`
= `2 + 5/62`
= `129/62 = 2 5/62` m or 2.8 m
50% of students jumped below `2 5/62` m and 50% above it.
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