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प्रश्न
Find x, if 9 x 3x = (27) 2x-3.
योग
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उत्तर
9 × 3x = (27) 2x−3
`3^2 xx 3^x = (3 xx 3 xx 3)^(2x-3)`
⇒ `3^(x + 2) = (3)^(3(2x - 3)`
`=> 3^(x + 2) = (3)^(6x - 9)`
Since, bases are same, compare them,
x + 2 = 6x − 9
6x − x = 9 + 2
`=>` 5x = 11
`=> x = 11/5 i.e. 2 1/5`
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