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प्रश्न
Find, which of the following points lie on the line x – 2y + 5 = 0 :
(–5, 0)
योग
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उत्तर
The given line is x − 2y + 5 = 0.
Substituting x = −5 and y = 0 in the given equation, we have:
L.H.S. = −5 − 2 × 0 + 5
= −5 − 0 + 5
= 5 − 5
= 0 = R.H.S.
Thus, the point (−5, 0) lie on the given line.
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Equation of a Line
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