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Find the Value of X, If ∣ ∣ ∣ X + 1 X − 1 X − 3 X + 2 ∣ ∣ ∣ = ∣ ∣ ∣ 4 − 1 1 3 ∣ ∣ ∣

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प्रश्न

Find the value of x, if

\[\begin{vmatrix}x + 1 & x - 1 \\ x - 3 & x + 2\end{vmatrix} = \begin{vmatrix}4 & - 1 \\ 1 & 3\end{vmatrix}\]

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उत्तर

\[\text{ Given }: \begin{vmatrix}x + 1 & x - 1 \\ x - 3 & x + 2\end{vmatrix} = \begin{vmatrix}4 & - 1 \\ 1 & 3\end{vmatrix}\]
\[ \Rightarrow \left( x + 1 \right)\left( x + 2 \right) - \left( x - 3 \right)\left( x - 1 \right) = 12 + 1\]
\[ \Rightarrow x^2 + 3x + 2 - x^2 + 4x - 3 = 13\]
\[ \Rightarrow 7x - 1 = 13\]
\[ \Rightarrow 7x = 14\]
\[ \Rightarrow x = 2\]

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अध्याय 5: Determinants - Exercise 6.1 [पृष्ठ १०]

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आर.डी. शर्मा Mathematics Volume 1 and 2 [English] Class 12
अध्याय 5 Determinants
Exercise 6.1 | Q 10.5 | पृष्ठ १०

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