Advertisements
Advertisements
प्रश्न
Find trinomial (quadratic expression), given below, find whether it is factorisable or not. Factorise, if possible.
x(2x - 1) - 1
Advertisements
उत्तर
Given expression : x(2x - 1) - 1
Now , x(2x - 1) - 1 = 2x2 - x - 1
Comparing with ax2 + bx + c, we get a = 2, b = - 1, and c = - 1
∴ b2 - 4ac = (- 1)2 - 4(2)(-1) = 1 + 8 = 9, which is a perfect square.
∴ 2x2 - x - 1 is factorisable.
Now, 2x2 - x - 1 = 2x2 - 2x + x - 1
= 2x( x - 1 ) + 1( x - 1 )
= ( 2x + 1 )( x - 1 )
APPEARS IN
संबंधित प्रश्न
Factorise.
m2 − 25m + 100
Factorise.
2x2 + x − 45
Factorise the following by splitting the middle term:
15a2 - 14a - 16
Factorise the following:
2x3 + 5x2y - 12xy2
Factorise the following:
y2 + 3y + 2 + by + 2b
Factorise the following:
5(3x + y)2 + 6(3x + y) - 8
Factorise the following:
(x + 4)2 - 5xy - 20y - 6y2
Factorise the following:
(p2 + p)2 - 8(p2 + p) + 12
Factorise the following:
12(2x - 3y)2 - 2x + 3y - 1
Factorise the following:
p4 + 23p2q2 + 90q4
