Question

Find the values of x, y, z if `[(x - 3, 3x - z),(x + y + 7, x + y + z)] = [(1, 0),(1, 6)]`

Answer 1

x – 3 = 1 ⇒ x = 1 + 3 ⇒ x = 4

3x – z = 0  ...(substitute the value of x)

3(4) – z = 0

12 – z = 0

∴ z = 12

x + y + z = 6

4 + y + 12 = 0

y + 16 = 6

y = 6 – 16

∴ y = – 10

The value of x = 4, y = – 10 and z = 12