Question

Find the value of x if `[(3x + y, -y),(2y -  x, 3)] = [(1, 2),(-5, 3)]`

Answer 1

`[(3x + y, -y),(2y -  x, 3)] = [(1, 2),(-5, 3)]`
Comparing the corresponding terms, we get.
-y = 2
⇒ y = -2
3x + y = 1
⇒  3x = 1 – y
⇒ 3x = 1 – (–2)
= 1 + 2 
= 3
⇒ x = `(3)/(3)`
= 1
Hence x = 1, y = –2.