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Find the value of the following: tan^–1 [2 cos (2  sin^–1  1/2)]

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प्रश्न

Find the value of the following:

`tan^-1 [2 cos (2  sin^-1  1/2)]`

योग
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उत्तर

Let `sin^-1  1/2 = x`.

Then, `sin x = 1/2 = sin (pi/6)`.

∴ `sin^-1  1/2 = pi/6`

∴ `tan^-1 [2  cos (2 sin^-1  1/2)]`

= `tan^-1 [2  cos (2 xx pi/6)]`

= `tan^-1 [2  cos  pi/3]`

= `tan^-1 [2 xx 1/2]`

= tan−1 1

= `pi/4`

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अध्याय 2: Inverse Trigonometric Functions - EXERCISE 2.2 [पृष्ठ २९]

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एनसीईआरटी Mathematics Part 1 and 2 [English] Class 12
अध्याय 2 Inverse Trigonometric Functions
EXERCISE 2.2 | Q 8. | पृष्ठ २९

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