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find the value of : tan 45 ° cos e c 30 ° + sec 60 ° c o 45 ° – 5 sin 90 ° 2 cos 0 ° - Mathematics

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प्रश्न

find the value of :

`( tan 45°)/ (cos ec30°) +( sec60°)/(co 45°) – (5 sin 90°)/ (2 cos 0°)`

योग
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उत्तर

`( tan 45°)/ (cos ec30°) +( sec60°)/(co 45°) – (5 sin 90°)/ (2 cos 0°) = (1)/(2) + (2)/(1)+(5)/(2)`

`= ( 1 + 4 – 5)/(2) = 0`

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अध्याय 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (A) [पृष्ठ २९१]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (A) | Q 2.2 | पृष्ठ २९१
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