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find the value of: cos2 60° + sec2 30° + tan2 45° - Mathematics

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प्रश्न

find the value of: cos2 60° + sec2 30° + tan2 45°

योग
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उत्तर

cos 60° + sec2 30° + tan2 45° = `(1/2)^2 + (2/sqrt3)^2 + 1^2`

= `(1)/(4) + (4)/(3) + 1`

= `( 3 + 16 + 12)/(12)`

= `(31)/(12)`

= `2(7)/(12)`

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अध्याय 23: Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] - Exercise 23 (A) [पृष्ठ २९१]

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सेलिना Concise Mathematics [English] Class 9 ICSE
अध्याय 23 Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]
Exercise 23 (A) | Q 1.6 | पृष्ठ २९१
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