Question

Find the value of: `((0.2 xx 0.14) + (0.5 xx 0.91))/((0.1 xx 0.2))`

Answer 1

Given, `((0.2 xx 0.14) + (0.5 xx 0.91))/((0.1 xx 0.2))`

∵ `0.2 = 2/10, 0.14 = 14/100` and `0.5 = 5/10`

`0.91 = 91/100, 0.1 = 1/10` and `0.2 = 2/10`

∴ `((0.2 xx 0.14) + (0.5 xx 0.91))/((0.1 xx 0.2))`

= `((2/10 xx 14/100) + (5/10 xx 91/100))/((1/10 xx 2/10))`

= `((2 xx 14)/1000 + (5 xx 91)/1000)/((1 xx 2)/100`

= `(28/1000 + 455/1000)/(2/100)`

= `((28  +  455)/1000)/(2/100)`

= `(483/1000)/(2/100)`

= `483/1000 xx 100/2`  ...[∵ Division is reverse of the multiplication]

= `483/(10 xx 2)`

= `241.5/10`

= 24.15