Find the supplementary/complementary angle

आकृति

∠ABD + ∠DBC = 90°

∠ABD + 46° = 90°

∠ABD = 90° − 46°

∠ABD = 44°

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अध्याय 4: Geometry - Exercise 4.2 [पृष्ठ ८१]

अध्याय 4 Geometry
Exercise 4.2 | Q 12. (iv) | पृष्ठ ८१

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90°

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