Question

Find the sum and product of the roots for the following quadratic equation

`3 + 1/"a" = 10/"a"^2`

Answer 1

3a² + a = 10

3a² + a – 10 = 0 comparing this with x² – (α + β)

x + αβ = 0

`"a"^2 - (- 1/3)"a" + ((-10)/3)` = 0

α + β = `(-1)/(3)`

αβ = `(-10)/(3)`