Question

Find the standard deviation of the first 21 natural numbers.

Answer 1

Here n = 21

The standard deviation of the first ‘n’ natural numbers,

= `sqrt(("n"^2 - 1)/12)`

1, 2, 3, 4, ..., 21 = `sqrt((21^2 - 1)/12)`

= `sqrt((441 - 1)/12)`

= `sqrt(440/12)`

= `sqrt(36.666)`

= `sqrt(36.67)`

= 6.055

= 6.06

The standard deviation of the first 21 natural numbers = 6.06