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Find the square of the given number. 93 - Mathematics

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प्रश्न

Find the square of the given number.

93

योग
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उत्तर

93= (90 + 3)2

= (90 + 3) (90 + 3)

= 90 (90 + 3) + 3 (90 + 3)

= 902 + 90 × 3 + 3 × 90 + 32

= 8100 + 270 + 270 + 9

= 8649

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अध्याय 6: Squares and Square Roots - Exercise 6.2 [पृष्ठ ९८]

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एनसीईआरटी Mathematics [English] Class 8
अध्याय 6 Squares and Square Roots
Exercise 6.2 | Q 1.4 | पृष्ठ ९८

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संबंधित प्रश्न

Write a Pythagorean triplet whose one member is 16.


What will be the units digit of the square of the following number?

52


What will be the units digit of the square of the following number?  

52698 


Which of the following triplet is pythagorean? 

 (18, 80, 82) 


Which of the following triplet pythagorean? 

(16, 63, 65)


Which of the following triplet  pythagorean? 

(12, 35, 38) 


Observe the following pattern 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) = \frac{2 \times 3 \times 4}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) = \frac{3 \times 4 \times 5}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) + \left( 4 \times 5 \right) = \frac{4 \times 5 \times 6}{3}\] 

and find the value of(1 × 2) + (2 × 3) + (3 × 4) + (4 × 5) + (5 × 6)


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

12 + 22 + 32 + 4+ ... + 102

 

 


Find the square of the following number: 

 575


For every natural number m, (2m – 1, 2m2 – 2m, 2m2 – 2m + 1) is a pythagorean triplet.


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