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प्रश्न
Find the square of `2"x"+1/"x"+1`
योग
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उत्तर
`(2"x"+1/"x"+1)^2=(2"x")^2+(1/"x")^2+(1)^2 +2xx2"x"xx1 /"x"+2xx1/"x"xx1+2xx1xx2"x"`
`=4"x"^2+1/"x"^2+1+4+2/"x"+4"x"`
`=4"x"^2+1/"x"^2+5+2/"x"+4"x"`
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