हिंदी

Find the slope of the tangent to the curve y = 2sin^2(3x) at x = π/6. - Mathematics

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प्रश्न

Find the slope of the tangent to the curve y = 2sin2(3x) at `x = π/6`.

योग
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उत्तर

Given, y = 2sin2(3x)

`dy/dx = 2 xx 2 sin (3x) cos (3x) xx 3`

= 6 × 2 sin (3x) cos (3x)

`dy/dx = 6 xx sin 6x`

Now, `dy/dx]_(at  x  =  π/6) = 6 xx sin π`

= 0

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2019-2020 (March) Delhi Set 1
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