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प्रश्न
Find the slope and y intercept of `sqrt(3x) + (1 - sqrt(3))y` = 3
योग
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उत्तर
The equation of a line is `sqrt(3x) + (1 - sqrt(3))y` = 3
`(1 - sqrt(3))y = sqrt(3) x + 3`
y = `(-sqrt(3)x)/(1 - sqrt(3)) + 3/(1 - sqrt(3))`
Slope (m) = `(-sqrt(3))/(1 - sqrt(3))`
= `(-sqrt(3)(1 + sqrt(3)))/((1 - sqrt(3))(1 + sqrt(3))`
= `(-sqrt(3) - 3)/(1 - 3)`
= `(-(sqrt(3) + 3))/(-2)`
= `(sqrt(3) + 3)/2`
y intercept = `3/(1 - sqrt(3))`
= `(3(1 + sqrt(3)))/((1 - sqrt(3))(1 + sqrt(3))`
= `(3 + 3sqrt(3))/(1 - 3)`
= `(3 + 3sqrt(3))/(-2)`
= `-(3(1 + sqrt(3)))/2`
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