Advertisements
Advertisements
प्रश्न
Find the roots of the following equation, if they exist, by applying the quadratic formula:
2x2 + x – 4 = 0
योग
Advertisements
उत्तर
The given equation is 2x2 + x – 4 = 0
Comparing it with ax2 + bx + c = 0 we get
a = 2, b = 1 and c = –4
∴ Discriminant, D = b2 – 4ac
= (1)2 – 4 × 2 × (–4)
= 1 + 32
= 33 > 0
So, the given equation has real roots.
Now, `sqrt(D) = sqrt(33)`
∴ `α = (-b + sqrt(D))/(2a)`
= `(-1 + sqrt(33))/(2 xx 2)`
= `(-1 + sqrt(33))/4`
∴ `β = (-b - sqrt(D))/(2a)`
= `(-1 - sqrt(33))/(2 xx 2)`
= `(-1 - sqrt(33))/4`
Hence, `((-1+sqrt(33)))/4` and `((-1 - sqrt(33)))/4` are the roots of the given equation.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
