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प्रश्न
Find the projection of the vector `hati - hatj` on the vector `hati + hatj`.
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उत्तर
Let `veca = hati - hatj`
and `vecb = hati + hatj`
`|vecb| = sqrt(1^2 + 1^2)`
`= sqrt(1 + 1)`
`= sqrt2`
Also, `veca. vecb = (hati - hatj)* (hati + hatj)`
= (1) (1) + (-1) (1)
= 1 - 1
= 0
∴ Projection of `vec a "on" vec b = (veca. vecb)/|vecb|`
`= 0/sqrt2`
= 0
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