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Find the product: (3x + y) (9x^2 – 3xy + y^2) - Mathematics

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प्रश्न

Find the product:

(3x + y) (9x2 – 3xy + y2)

योग
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उत्तर

Given: (3x + y)(9x2 – 3xy + y2)

Step-wise calculation:

We use the distributive property to multiply each term in the first bracket by each term in the second bracket:

= (3x)(9x2) + (3x)(–3xy) + (3x)(y2) + (y)(9x2) + (y)(–3xy) + (y)(y2)

Calculate each term:

= 27x3 – 9x2y + 3xy2 + 9x2y – 3xy2 + y3

Combine like terms:

27x3 + (–9x2y + 9x2y) + (3xy2 – 3xy2) + y3 

= 27x3 + 0 + 0 + y3

So the product is 27x3 + y3.

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अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 3 Expansions
Exercise 3A | Q 11. (i) | पृष्ठ ६४
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