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प्रश्न
Find the product:
(3x + y) (9x2 – 3xy + y2)
योग
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उत्तर
Given: (3x + y)(9x2 – 3xy + y2)
Step-wise calculation:
We use the distributive property to multiply each term in the first bracket by each term in the second bracket:
= (3x)(9x2) + (3x)(–3xy) + (3x)(y2) + (y)(9x2) + (y)(–3xy) + (y)(y2)
Calculate each term:
= 27x3 – 9x2y + 3xy2 + 9x2y – 3xy2 + y3
Combine like terms:
27x3 + (–9x2y + 9x2y) + (3xy2 – 3xy2) + y3
= 27x3 + 0 + 0 + y3
So the product is 27x3 + y3.
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]
