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प्रश्न
Find the principal value of the following:
`"cosec"^(-1) (-sqrt(2))`
योग
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उत्तर
Let `"cosec"^(-1) (-sqrt(2)) = y`
Then, `"cosec" y = -sqrt(2)`
= `-"cosec" (pi/4)`
= `"cosec" (-pi/4)`
We know that the range of the principal value branch of cosec−1 is `[-pi/2, pi/2] - {0}` and `"cosec" (-pi/4) = -sqrt(2)`.
Therefore, the principal value of `"cosec"^(-1) (-sqrt(2))` is `-pi/4`.
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