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प्रश्न
Find the number of permutations of letters of the following word: SHANTARAM
योग
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उत्तर
The word SHANTARAM has 9 letters of which ‘A’ is repeated 3 times and the rest all are different.
Hence, the number of permutations
= `("n"!)/("p"!)`
= `(9!)/(3!)`
= `(9 xx 8 xx 7 xx 6 xx 5 xx 4 xx 3!)/(3!)`
= 60480
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 6: Permutations and Combinations - Exercise 6.4 [पृष्ठ ८२]
