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प्रश्न
Find the number of permutations of letters in the following word:
SHANTARAM
योग
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उत्तर
In the word 'SHANTARAM', the number of letters is n = 9 of which A repeats thrice, i.e., p = 3 and rest are distinct.
∴ the number of distinct permutations of the letters
= `("n"!)/("p"!)`
= `(9!)/(3!)`
= `(9 xx 8 xx 7 xx 6 xx 5 xx 4 xx 3!)/(3!)`
= 9 × 8 × 7 × 6 × 5 × 4
= 60480.
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Permutations and Combination - Exercise 3.4 [पृष्ठ ५७]
