Question

Find the nature of the roots of the following quadratic equation: 

`3x^2 - 2sqrt(6)x + 2 = 0`

Answer 1

The given equation is `3x^2 - 2sqrt(6)x + 2 = 0`

This is of the form ax² + bx + c = 0, where a = 3, b = `-2sqrt(6)` and c = 2 

∴ Discriminant, D = b² – 4ac

= `(-2sqrt(6))^2 - 4 xx 3 xx 2`

= 24 – 24

= 0 

Hence, the given equation has real and equal roots.