Question

Find the nature of the roots of the equation `3x^2 - 4sqrt(3)x + 4 = 0`.

Answer 1

Given, `3x^2 - 4sqrt(3)x + 4 = 0`

Here, a = 3, b = `-4sqrt(3)`, c = 4

Discriminant (D) = b² – 4ac

= `(-4sqrt(3))^2 - 4 xx 3 xx 4`

= 48 – 48

= 0

So, roots are real and equal.