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Find the modulus and amplitude of the following complex number. −4 − 4i

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प्रश्न

Find the modulus and amplitude of the following complex number.

−4 − 4i

योग
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उत्तर

Let z = −4 − 4i.

Here, a = −4, b = −4 i.e., a < 0, b < 0

∴ |z| = `sqrt(a^2 + b^2)`

= `sqrt((-4)^2 + (-4)^2`

= `sqrt(16 + 16)`

= `sqrt(32)`

= `4sqrt(2)`

Here, (−4, −4) lies in 3rd quadrant.

The amplitude (or argument) of a complex number z = a + bi is the angle θ formed with the positive real axis in the complex plane, and it is given by:

∴ θ = `tan^-1(b/a)`

= `tan^-1((-4)/(-4))`

= `tan^-1(1)`

= `tan^-1 (tan  pi/4)`

θ = `pi/4`

However, since the complex number −4−4i lies in the third quadrant (both real and imaginary parts are negative), the angle needs to be adjusted. The angle in the third quadrant is:

θ = `pi  + pi/4`

θ = `(5pi)/4`

Hence, modulus = `4sqrt2`  and

Amplitude (θ) = `(5pi)/4`

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अध्याय 1: Complex Numbers - Exercise 1.3 [पृष्ठ १५]

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बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
अध्याय 1 Complex Numbers
Exercise 1.3 | Q 1. (v) | पृष्ठ १५

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