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Find the mean: Marks (below) 10 20 30 40 50 60 70 80 90 100 No. of students 5 9 17 29 45 60 70 78 83 85 - Mathematics

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प्रश्न

Find the mean:

Marks (below) 10 20 30 40 50 60 70 80 90 100
No. of students 5 9 17 29 45 60 70 78 83 85
योग
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उत्तर

Step 1: Create a frequency distribution table

The “Marks (below)” represent the upper limits of class intervals. Since they increase by 10, our intervals will be 0 – 10, 10 – 20, etc. To find the frequency (f) for each interval, we subtract the previous cumulative frequency from the current one.

Class Interval
(Marks)
Midpoint
(xi)
No. of students
(cf)
Frequency
(fi)
fi × xi
0 – 10 5 5 5 25
10 – 20 15 9 9 – 5 = 4 60
20 – 30 25 17 17 – 9 = 8 200
30 – 40 35 29 29 – 17 = 12 420
40 – 50 45 45 45 – 29 = 16 720
50 – 60 55 60 60 – 45 = 15 825
60 – 70 65 70 70 – 60 = 10 650
70 – 80 75 78 78 – 70 = 8 600
80 – 90 85 83 83 – 78 = 5 425
90 – 100 95 85 85 – 83 = 2 190
Total     Σfi = 85 Σfixi = 4115
Step 2: Calculate the mean

The formula for the mean `(barx)` of grouped data is:

`barx = (sumf_ix_i)/(sumf_i)`

Substituting the values from our table:

`barx = 4115/85`

`barx ≈ 48.41`

The mean marks of the students is approximately 48.41.

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अध्याय 21: Measures of central tendency - Exercise 21A [पृष्ठ ४६२]

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नूतन Mathematics [English] Class 10 ICSE
अध्याय 21 Measures of central tendency
Exercise 21A | Q 10. | पृष्ठ ४६२
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