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प्रश्न
Find the inclination of the line whose slope is `1/sqrt3`.
Find the inclination of a line whose slope (gradient) is `1/sqrt3`.
योग
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उत्तर
If tan θ is the slope of a line, then the inclination of the line is tan θ
Here the slope of a line is `(1)/sqrt(3)`; then tan θ = `(1)/sqrt(3)`
Now,
tan θ = `(1)/sqrt(3)`
tan θ = tan 30°
∴ θ = 30°
Hence, the inclination of the given line is θ = 30°.
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