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प्रश्न
Find the gradient and the equation of the line passing through the points:
$$\mathrm{A}(-2, 1)$$ and $$\mathrm{B}(3, -4)$$
योग
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उत्तर
The gradient of a line passing through $$(x_1, y_1)$$ and $$(x_2, y_2)$$ is $$m = \frac{y_2 - y_1}{x_2 - x_1}$$ and the equation of the line is $$y - y_1 = m(x - x_1)$$
For $$\mathrm{A}(-2, 1)$$ and $$\mathrm{B}(3, -4)$$:
$$m = \frac{-4 - 1}{3 - (-2)}$$
$$= \frac{-5}{5}$$
$$= -1$$
Equation of the line:
$$y - 1 = -1(x - (-2))$$
$$y - 1 = -(x + 2)$$
$$y - 1 = -x - 2$$
$$x + y + 1 = 0$$
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अध्याय 14: Equation of a Straight Line - EXERCISE 14A [पृष्ठ २२३]
