Question

Find the equation of a straight line which has slope `(−5)/4` and passing through the point (– 1, 2).

Answer 1

Slope of a line (m) = `(−5)/4` 

The given point (x₁, y₁) = (−1, 2)

Equation of a line is y – y₁ = m (x – x₁)

y – 2 = `(-5)/4(x + 1)`

5(x + 1) = − 4(y – 2)

5x + 5 = − 4y + 8

5x + 4y + 5 – 8 = 0

5x + 4y – 3 = 0

The equation of a line is 5x + 4y – 3 = 0