Question

Find the equation of a line whose slope $$= \frac{3}{4}$$ and $$y$$-intercept $$= -4$$.

Answer 1

The equation of a line with slope $$m$$ and $$y$$-intercept $$c$$ is given by $$y = mx + c$$.

Here, $$m = \frac{3}{4}$$ and $$c = -4$$:

$$y = \frac{3}{4}x - 4$$ 

Multiplying both sides by $$4$$: 

$$4y = 3x - 16$$

$$3x - 4y - 16 = 0$$