Question

Find the equation of a line whose intercepts on the x and y axes are given below

`- 5, 3/4`

Answer 1

x intercept (a) = – 5, y intercept (b) = `3/4`

Equation of a line is `x/"a" + y/"b"` = 1

⇒ `x/(-5) + y/(3/4)` = 1

`x/(-5) + (4y)/3` = 1   ...(L.C.M. of 5 and 3 is 15)

– 3x + 20y = 15

– 3x + 20y – 15 = 0

3x – 20y + 15 = 0

∴ Equation of a line is 3x – 20y + 15 = 0