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प्रश्न
Find the equation of a line passing through the point (2, −5) and making an intercept of −3 on the Y-axis.
योग
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उत्तर
Given values:
- Point: (2, −5)
- Y-intercept (c): −3 (This means the line passes through the point (0, −3)
Using the slope formula with points (2, −5) and (0, −3):
`m = (y_2 - y_1)/(x_2 - x_1)`
`m = (-3 - (-5))/(0 - 2)`
`m = 2/-2`
∴ m = −1
Using the slope-intercept form y = mx + c:
y = −1x + (−3)
y = −x − 3
Rearranging into the standard form (Ax + By + C = 0):
x + y + 3 = 0
Hence, the equation of a line passing through the points is x + y + 3 = 0.
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