Question

Find the distance of the origin from the line 7x + 24y – 50 = 0

Answer 1

Let p be the perpendicular distance of origin from the line 7x + 24y – 50 = 0

Here, a = 7, b = 24, c = – 50

∴ p = `|"c"/sqrt("a"^2 + "b"^2)|`

∴ p = `|(-50)/sqrt(7^2 + 24^2)|`

= `|(-50)/sqrt(49 + 576)|`

= `|(-50)/25|`

= 2 units