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प्रश्न
Find the differential dy for the following functions:
y = `(3 + sin(2x))^(2/3)`
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उत्तर
dy = `{2/3[3 + sin(2x)]%^((-1)/3) [(cos2x)(2)]} "d"x`
= `{4/3(3 + sin 2x)^((-1)/3) (cos 2x)} "d"x`
= `{4/3 (3 + sin 2x)^((-1)/3) (cos 2x)} "d"x`
= `{4/3 (cos2x)/(3 + sin2x)^(1/3)} "d"x`
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